Question

6) Experimental analysis of a
Compound containing the elements
x,y,z on analysis gave the following
data. x= 32 %, y = = 24 %, z = 44 %.
The relative number of atoms of x, y
and z are 2, 1 and 0.5, respectively.
(Molecular mass of the compound is
400 g) Find out.
i) The atomic masses of the element
X,Y,Z.
ii)
Empirical
formulaa
of
the
Compound and
iii) Molecular
formula of the
Compound.​

Answer 1

Explanation:

Element x = 32% ; y = 24% ; z = 44% Relative number of atoms x = 2 ; y = 1 ; z = 0.5 Molar mass of the compound = 400 g. 1. Atomic mass of the element. Relative number of atoms = (Percentage composition) / (Atomic mass) ∴ Atomic mass = (Percentage composition) / (Relative No. of atoms) Atomic mass x = 32/2 = 16 Atomic mass y = 24/1 = 24 Atomic mass z = 44/0.5 = 88 2. Empirical formula of the compound x4 y2 z1 Molecular mass of the compound = 400 n = (Molecular formula of the compound) = 400/200 = 2 3. Molecular formula of the compound = x8 y4Read more on Sarthaks.com - https://www.sarthaks.com/914826/experimental-analysis-compound-containing-the-elements-analysis-gave-the-following-data

Answer 2

Explanation:

x2y1z0.5

so now multiply all by factor of 2

X4Y2Z is the molecular formula