6. Express cos83° - sec76° in terms of trigonometric ratios of angles between 0 and 45°
Answers
Answered by
38
Answer:
(2 sin ^2 . cos 7 - 1) / 2 (sin7.cos7)
Step-by-step explanation:
cos 83 - sec 76
sin ( 90 - 83 ) - cosec ( 90 - 76 )
sin 7 - cosec 14 ..........[ sin 2x = 2 sinx.cosx]
sin 7 - 1/2 sin 7.cos 7
therefore, [2sin^2(7).cos (7)] - 1/2sin 7.cos 7
Answered by
15
Answer:
cos83-sec76=cos(90-7) -sec(90-14)
=(sin7-cosec14)
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