Question

6. Factorisation of x + 1 is
(a) (x + 1)(x x+1)
(c) (x + 1)(x x 1)
(b) (x + 1)(x² + x +
(d) (x + 1)(x²+1)​

Answer 1

Step-by-step explanation:

Let assume (x + 1) is a factor of x3 + x2 + x+1. (-1)3 + (-1)2 + (-1) + 1 = 0 ⇒ -1+1-1 + 1 = 0 ⇒ 0 = 0 Hence, our assumption is true.