Question

6) Factorise 2x +8xy​

Answer 1

2x+8xy = 2x(1+4y)

There needs to be 20 characters atleast hehe

Answer 2

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Given :

2x+4y−8xy−1

We can further write it as

2x+4y−8xy−1=2x−1−8xy+4y

By taking common terms out

2x+4y−8xy−1=(2x−1)−4y(2x−1)

So we get,

2x+4y−8xy−1=(2x−1)(1−4y)

Other type of Answer :-

STEP 1:

Equation at the end of step 1

2x - 23xy2

STEP2:

STEP3:

Pulling out like terms 3.1

Pull out like factors :

2x - 8xy2 = -2x • (4y2 - 1)

Trying to factor as a Difference of Squares:

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