Question

6. Factorise: x3 - (1/x3 ) - 14
[HINT: x3 - (1/x3 )-8-6]
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Answer 1

Answer:

(x - 1/x - 2)^3

Step-by-step explanation:

x^3 - (1/x)^3 - (2)^3 - 3×(x)×(1/x)×(2)

from (a^3-b^3-c^3-3abc) =(a-b-c)^3

then

(x-1/x-2)^3 answer

Answer 2

Answer:

(x-1/x-2)(x²+1/x²-2/x+2x+5)

you can refer attachment

Step-by-step explanation:

First break -14 as -8 and -6

then use identity:

a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca)

Hope you got your answer!!!