Question

6
Factorize using suitable identity: 25-a2-b2- 2ab​

Answer 1

Answer:

dont know sorry XD 74327

Answer 2

Answer:

25-(a^2+b^2+2ab) [(a^2+b^2+2ab)=(a+b)^2] identity

(5)^2-(a-b)^2. [a^2-b^2=(a+b)(a-b)] identity

(5+a-b)(5-a+b)

this is answers