Math, asked by fulendebnath121, 9 months ago

6. Find out the lowest number which leaves 3 as remainder in each case when it is
divided by 9, 2, 16 and 20.

Answers

Answered by sk0768173ph3gfb

1

Answer:

lcm of 9,2 16, 20=20×4×9=720

required number=720+3=723

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