Question

6. Find P(1),P(-2) for the polynomial
P(x)=(x+2)(x-2).​

Answer 1

Step-by-step explanation:

P(x)=(x+2)(x-2)

If X=1,

p(1)=(1+2)(1-2)

= 3-1

=2

If X= -2,

p(-2)=(-2+2)(-2-2)

= 0

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Answer 2

$p(x) = (x + 2)( x - 2)$

$p(x) = {x }^{2} - {2}^{2}$

$p(x) = {x}^{2} - 4$

$p(1) \: substituting \: value \: of\: x \: as \: 1$

$p(1) = {1}^{2} - 4$

$p(1) = - 3$

$p( - 2) = { - 2}^{2} - 4 \\p( - 2) = 4 - 4 \\p( - 2) = 0$

So, P(1) = -3 and P(-2) = 0