Question

6. Find p(1),p(2) for the polynomials
Al p(t) = 2+t+2+2-13
B] p(x) = (x-1)(x+1)​

Answer 1

Answer:

(i) p(y)=y 2−y+1p(0)=(0) 2−(0)+1=0+0+1=1p(1)=(1) 2−(1)+1=1−1+1=1p(2)=(2) 2−(2)+1=4−2+1=3

(ii) p(t)=2+t+2t 2−t 3p(0)=2+(0)+2(0) 2−t 3

=2+0+0−0=2p(1)=2+(1)+2(2) 2−(1) 3

=2+1+2−1=4p(2)=2+(2)+2(2) 2 −(2) 3 =2+2+8−8=4

(iii) p(x)=x 3p(0)=(0) 3=0p(1)=(1) 3 =1p(2)=(2) 3 =8

(iv) p(x)=(x−1)(x+1)

p(0)=(0−1)(0+1)=(−1)(1)=−1

p(1)=(1−1)(1+1)=(0)(2)=0

p(2)=(2−1)(2+1)=(1)(3)=3

Answer 2

Step-by-step explanation:

ans equals to 1 please mark as brainliest