Question

6. Find the altitude of a triangle if its base is
12 cm and area is 48 cm2.
(2)
with explanation plz
​

Answer 1

GIVEN:

• Base of the triangle = 12 cm
• Area of triangle = 48 cm²

TO FIND:

• What is the height of the triangle ?

SOLUTION:

Let the height of the triangle be 'h' cm

To find the area of triangle, we use the formula:-

$\large{\boxed{\bf{\star \: AREA = \dfrac{1}{2} \times BASE \times HEIGHT \: \star}}}$

• BASE = 12 cm
• HEIGHT = h cm
• AREA = 48 cm²

According to question:-

➜ 48 = $\sf{\dfrac{1}{2}}$ $\times$ 12 $\times$ h

➜ 48 = 6h

➜ $\sf{\cancel\dfrac{48}{6}}$ = h

❮ 8 cm = h ❯

❝ Hence, the height/altitude of the triangle is 8 cm ❞

______________________

Answer 2

GIVEN:-

b=12cm

area=${<strong>4</strong><strong>8</strong><strong>c</strong><strong>m</strong><strong>^</strong><strong>2</strong>}$

TO FIND:-

h=?

solution:-

WE KNOW THE AREA OF TRIANGLE AS

$= > \frac{1}{2} \times b \times h$

now, put the given values.....

$\frac{1}{2} \times 12 \times h = {48cm}^{2}$

$= > \frac{1}{ \cancel2} \times \cancel{12} \times h = 48$

$= > 6 \times h = 48$

$= > h = \frac{ \cancel{48}}{ \cancel 6}$

$= > h = 8cm$

so, the height is

$\boxed{8cm}$