Math, asked by abhishekranjan809213, 3 months ago

6. Find the approximate value of the square root
2 places of
decimal.
(i) 0.8​

Answers

Answered by ss9113216gmailcom
0

Answer:

2\jh

Step-by-step explanation:

4\5 0 chera pata nahi kya likha hai vah wale ko sst the cost of the fan of

Answered by joinanu14
0

Answer:

\sqrt{0.8}=0.89

0.8

=0.89

Step-by-step explanation:

Given : Number \sqrt{0.8}

0.8

To find : The square root of 0.8 up to two places of decimal.

Solution :

Let x=\sqrt{0.8}x=

0.8

Squaring both side,

x^2=0.8x

2

=0.8

x^2=\frac{8}{10}x

2

=

10

8

Multiply and divide by 10,

x^2=\frac{80}{100}x

2

=

100

80

x^2=\frac{(4\sqrt5)^2}{(10)^2}x

2

=

(10)

2

(4

5

)

2

Now, Taking root both side,

x=\frac{4\sqrt5}{10}x=

10

4

5

x=\frac{4\times 2.23}{10}x=

10

4×2.23

x=\frac{8.92}{10}x=

10

8.92

x=0.892x=0.892

Up to two decimal places \sqrt{0.8}=0.89

0.8

=0.89

Similar questions