Question

6. Find the area of a parallelogram whose base is
26 cm and the corresponding altitude is 15 cm.
Also find the other altitude of the parallelogram if
othe side is 13 cm.​

Answer 1

Answer:

The area of parallelogram is 390$cm^{2}$ and the length of the other altitude is 30cm.

Step by Step Explanation:

Base of the parallelogram = 26cm

Altitude of the parallelogram = 15cm

Area of Parallelogram  = b × h

                                       = 26 x  15

                                       = 390$cm^{2}$

Now let's find the length of the other altitude whose base is 13cm.

We know that,

Area of parallelogram = 390$cm^{2}$

b x h = 390

Here the base is 13cm.

∴ 13 x h = 390

h = $\frac{390}{13}$

h = 30cm

∴ The length of the other altitude is 30cm.

Answer 2

Area of parallelogram= height * base
One height= 15 Cm
Corresponding base = 26 Cm
Area = 390 cm^2

Now , the area of parallelogram always remains the same for every height or base
So different bases and corresponding heights of the same parallelogram would always give the same area .

So ,

Base = 13 Cm
Corresponding altitude = unknown
Let the unknown altitude corresponding to the base 13 Cm be y

So the equation so formed is

13*y= 390
( 390 is in RHS because area always remains same for all the heights and bases of a same parallelogram, and we had found out area to be 390 cm^2)

Using transposition method :-
y = 390/13
So y = 30 Cm
So the second answer is 30 Cm .

I hope this answer will help you and do give me a thanks if you think that answer was properly explained.