Math, asked by malalukka27, 11 months ago

6. Find the area of a trapezium whose parallel
sides are 22 cm and 8 cm and the distance
between them is 10 cm.​

Answers

Answered by StudiousSam
16

Answer: 150 cm²

Step-by-step explanation:

Area of trapezium = 1/2 × (sum of parallel sides) × height.

= 1/2 × 30×10

= 150cm²

Answered by StarlightPhoenix
6

Answer:

The area of a Trapezium is :-

➵ 150 cm²

Step-by-step explanation:

Given:-

The parallel sides of a Trapezium are 22 cm and 8 cm respectively

The distance between their parallel sides are 10 cm

To find:-

The area of the Trapezium

Solution:-

The dimensions of the Trapezium is given to us as it's parallel sides are 22 cm and 8 cm respectively and the distance between them is 10 cm

Altitude is also known as distance between the parallel sides

Area of Trapezium = 1/2 × (sum of it's parallel sides) × Altitude

  • Parallel sides are 22 cm and 8 cm
  • Altitude is 10 cm

Applying formula:-

⇒ Area of trapezium = 1/2 × (22 cm + 8 cm) × 10 cm

⇒ Area of trapezium = 1/2 × 30 cm × 10 cm

⇒ Area of trapezium = 15 cm × 10 cm

⇒ Area of trapezium = 150 cm²

Answer:-

Hence, The area of the Trapezium is 150 cm² .

-:More Information:-

⇒ Area of square = (side)²

⇒ Area of rectangle = (l×b)

⇒ Area of triangle = 1/2 × base × height

⇒ Area of Circle = π r²

⇒ Area of rhombus = ( p q )/2

⇒ Area of parallelogram = base × height

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