Question

6. Find the area of the quadrilateral, the coordinates of whose vertices are (2, 1), (6, 0)
(5,-2) and (-3,-1.

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Answer 1

Answer:

we can't tell you like in typing because it is drawn in the graph OK

2=x ,1=y

mean (2,1) (6,0) ... or..... is written (x,y) form

Step-by-step explanation:

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Answer 2

Answer:

15 units²

Step-by-step explanation:

a = √[(- 3 - 2)² + (- 1 - 1)²] = √29 ≈ 5.3852

b = √[(2 - 6)² + (1 - 0)²] = √17 ≈ 4.1231

c = √[(- 3 - 6)² + (- 1 - 0)²] = √82 ≈ 9.0554

$P_{1}$ = √29 + √17 + √82 ≈ 18.564 , $s_{1}$ = 9.282 , $A_{1}$ ≈ 6.5 units²

e = √[(5 - 6)² + (- 2 - 0)²] = √5 ≈ 2.2366

f = √[(-3 - 5)² + (- 1 + 2)²] = √65 ≈ 8.0622

c = √[(- 3 - 6)² + (- 1 - 0)²] = √82 ≈ 9.0554

$P_{2}$ ≈ 19.3544 , $s_{2}$ = 9.6777 , $A_{2}$ ≈ 8.5 units²

A = $A_{1}$ + $A_{2}$ = 6.5 + 8.5 = 15 units²