Question

6 Find the area of the quadrilateral whose vertices are
taken in order are (-1,6), (-3,-9), (5, -8) and (3,9).​

Answer 1

Step-by-step explanation:

let the vertical of quadrilateral be

A(-1,6)

B(-3,-9)

C(5,-8)

D(3,9)

joining AD

these are 2 triangle formed by ABD and ACD

Hence , Area of quadrilateral ABCD = Area of ∆ ABD + Are of ∆ ACD