Question

6. Find the common difference of an AP whose 6th term is 12 and the th term is 22
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Answer 1

Answer:

Given, in an A.P a6 = 12 and a8 = 22 We know that an = a + (n – 1)d So, a6 = a + (6-1)d = a + 5d = 12 …. (i) And, a8 = a + (8-1)d = a + 7d = 22 ……. (ii) Solving (i) and (ii), we have (ii) – (i) ⇒ a + 7d – (a + 5d) = 22 – 12 2d = 10 d = 5 Putting d in (i) we get, a + 5(5) = 12 a = 12 – 25 a = -13 Thus, for the A.P: a = -13 and d = 5 So, the nth term is given by an = a + (n-1)d an = -13 + (n-1)5 = -13 + 5n – 5 ⇒ an = 5n – 18Read more on Sarthaks.com - https://www.sarthaks.com/652036/find-the-second-term-and-the-nthterm-of-an-a-p-whose-6thterm-is-12-and-the-8thterm-is-22

Hence, the second term is given by a2 = 5(2) – 18 = 10 – 18 = -8

Answer 2

Answer:

There is your solution....