Question

6. Find the coordinates of the point which divides the line segment joining (3, 4) and
(–6, 2) in the ratio 3 : 2 externally.
COORDINATE
GEOMETRY Chapter 5 TNSCERT 10

Answer 1

here is your ans ....hope it will help

Answer 2

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The point which divides the line

segment joining the points ( x1,y1 )

and ( x2 , y2 ) externally in the

ratio m1 : m2 is

x = ( m1x2-m2x1 )/( m1 - m2 ),

y = ( m1y2 - m2y1 )/( m1 - m2 )

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Let ( x , y ) is a point which divides

the line segment joining

A( x1, y1 ) = ( 3 , 4 ) and

B( x2, y2 ) = ( -6 , 2 ) in the ratio

m1 : m2 = 3 : 2 externally .

x = [ 3×(-6)-2×3 ]/( 3 - 2 )

x = ( -18 - 6 )/1

x = -24

y = [ 3 × 2 - 2 × 4 ]/( 3 - 2 )

y = ( 6 - 8 )/1

y = -2

Therefore ,

( x , y ) = ( -24 , -2 )

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