6.
Find the dimensions of a rectangle whose perimeter is 28 meters and whose area is 40
square meters,
Answers
Answered by
1
Step-by-step explanation:
Given :- Perimeter of rectangle = 28
2 (l + b ) = 28
l + b = 14
l = 14 - b --- (i)
area = 40
l × b = 40
from (i)
( 14 -b ) × b = 40
(14 - b²) = 40
b² - 14b + 40 = 0
After spilliting the zeros you will get...
b²-10b-4b+40 = 0
b(b-10)-4(b-10) = 0
(b-4)(b-10) = 0
(length) = 10
(breadth) = 4
hope it helps
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Answered by
0
L=10
B=4
Step-by-step explanation:
2(l+b)=28
l+b=14
l=14-b
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