Question

6.
Find the dimensions of a rectangle whose perimeter is 28 meters and whose area is 40
square meters,​

Answer 1

Step-by-step explanation:

Given :- Perimeter of rectangle = 28

2 (l + b ) = 28

l + b = 14

l = 14 - b --- (i)

area = 40

l × b = 40

from (i)

( 14 -b ) × b = 40

(14 - b²) = 40

b² - 14b + 40 = 0

After spilliting the zeros you will get...

b²-10b-4b+40 = 0

b(b-10)-4(b-10) = 0

(b-4)(b-10) = 0

(length) = 10

(breadth) = 4

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Answer 2

L=10

B=4

Step-by-step explanation:

2(l+b)=28

l+b=14

l=14-b