Question

6. Find the dimensions of a x b in the relation-
P=b-x2/a.t where P is power, x is distance, t is time, a&b are constants.
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Answer 1

Answer:

Explanation:

The given relation is P=b−x2at

As x2 is subtracted from b, therefore, the

dimensions of are of x2,i.e.,b=[L2]

we can rewrite relation (i) as P=L2at

or a=L2Pt=L2[ML2T−3][T]=[M−1L0T2]