6. Find the equation of straight line passing through the points (-2,5) which cuts off the equal interceps in magnitude but opposite in sign on the axes.
Answers
Answered by
0
Step-by-step explanation:
ANSWER
(1)
a
x
+
a
y
=1
⇒x+y=a
The above lines passes through a point (5,6) such that,
5+6=a
⇒a=11
Therefore, required equation is x+y=11
(2) Here there may be two cases
case-1:
−a
x
+
a
y
=1
⇒y−x=a
The above lines passes through a point (5,6) such that,
6−5=a
⇒a=1
Therefore, required equation is y−x=1
case-2:
a
x
+
−a
y
=1
⇒x−y=a
The above lines passes through a point (5,6) such that,
5−6=a
⇒a=−1
Therefore, required equation is x−y=−1
please follow me
Similar questions