Question

6. Find the greatest number that divides 846, 1107 and
1238 leaving remainders of 1, 2 and 3, respectively.​

Answer 1

we need to find hcf for that no

pf of 846 = 2*3*7*23

pf of 1107 = 3³*41

pf of 1238 = 2*619

coz 619 is a prime number

so answer is 1