Question

6.
Find the length of the tangent to a circle with centre 'O' and radius = 5 cm
from a point 'P' so that OP = 13 cm.​

Answer 1

Answer:

therefore, by pythagoras theorem

op² = oq² + qp²

the length of the tangent is 12 cm

Answer 2

Answer:

since we have given That Radius =5cm and OP =13cm

Then Using Pythogorous Theorm

(H)^2 =(B)^2 + (P)^2

OP^2=(OR)^2 + (PR)^2

(13)^2=(5)^2 +(PR)^2

(169)=(25) + (PR)^2

(PR)^2= (144)

(PR)=√144=12cm

PR=12cm