Question

6.
Find the median of the following cumulative frequency distribution graphically and verify it by actual
calculation:
Below Below Below Below Below Below Below Below
Marks
38 40
42
44 46 48 50 52
No of
0
3
5
9.
14
28
32
35
students
3​

Answer 1

Answer:

We are given the cumulative frequency distribution. So, we first construct a frequency table from the given cumulative frequency distribution and then we will make necessary computation to compute median.

Class intervalsFrequency (f)Cumulative frequency (c.f.)20-304430-40121640-50143050-60164660-70206670-80168280-90109290-1008100N=∑fi=100Here, N=∑fi=100∴2N=50

We observe that the cumulative frequency just greater than 2N=50 is 66 and the corresponding class is 60−70.

So, 60−70 is the median class. 

∴l=60,f=20,F=46 and h=10

Now,

Median =l+f2N−F×h

⇒Median=60+2050−46×10=62

Answer 2

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