Question

6. Find the nature of roots of the quadratic equation 2x2-6x+3=0
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Answer 1

Step-by-step explanation:

a = 2. b = -6 c = 3

D = b² - 4ac

D = (-6)² - [ (4)(2)(3) ]

D = 36 - 24

D = 12

as D > 0, the given quadratic equation has real and distinct or unequal roots

Answer 2

Answer:

2×square - 6×+3=0

Here,a=2,b= -6 and c=3

Discriminant= b square-4ac

=(-6 square)- 4×2×3

=36-24

=12

12 greater than 0

=It has two real and unequal roots