Question

6. Find the number of sides of a regular polygon whose each exterior angle is
(a) twice of its interior angle
(b) half of its interior angle.
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Answer 1

Answer:

let the exterior be x

so interior be 2x

x+2x=360

3x=360

x=360÷3

x=120

120 is Answer

I think

Answer 2

Answer:

Step-by-step explanation:

)a) Let the No of sides=n

its external angle =360/n

and interior angle

=(n-2)*180/n

as per question

360/n=2( n-2)*180/n

2=2(n-2)

2=2n-4

2n=6, n=3

so it is a triangle

b) Here as per question

as per question

360/n=1/2( n-2)*180/n

360=90(n-2)

4=n-2

n=6

Hence it is Hexagon