Question

6.
Find the number which when divided by 16, 20 and 40 leaves the same
remainder 4.​

Answer 1

Step-by-step explanation:

first do the lcm of 16,20,and40

then add the 4 to the annswer which you have got

I hope it's help full. to you

if not understand I will explain clealrly

Answer 2

Concept:

The required least number will be the LCM of the numbers 16, 20, and 40 added to the given remainder.

Given:

The given numbers are 16, 20, and 40.

The remainder is 4.

Solution:

First, we will find the LCM of the given numbers 16, 20, and 40 by the prime factorization method.

$16=2\times2\times2\times2$

$20=2\times2\times5$

$40=2\times2\times2\times5$

The LCM of $16,20$ and $40=2\times2\times2\times2\times5$

                                         $=80$

The required number$=$ LCM of $16,20$ and $40+$ remainder

                                   $=80+4$

                                   $=84$

Hence, the number which when divided by 16, 20 and 40 leaves the same remainder 4 is 84.

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