Question

6 Find the point on X-axis which is equidistant from P(2,-5) and Q(-2,9).
6. Find the distances between the following points.​

Answer 1

Answer:

Let point R be on the X-axis which is equidistant from points P and Q. Point R lies on X-axis. ∴ its y co-ordinate is 0. Let R = (x, 0) R is equidistant from points P and Q. ∴ PR = QR = (x−2)2+[0−(−5)]2−−−−−−−−−−−−−−−−−√(x−2)2+[0−(−5)]2 ....[By distance formula] = [x−(−2)]2+(0−9)2−−−−−−−−−−−−−−−−−√[x−(−2)]2+(0−9)2 ∴ (x – 2)2 + [0 – (-5)]2 = [x – (- 2)]2 + (0 – 9)2 …[Squaring both sides] ∴ (x – 2)2 + (5)2 = (x + 2)2 + (-9)2 ∴ 4 – 4x + x2 + 25 = 4 + 4x + x2 + 81 ∴ – 8x = 56 ∴ x = -7 ∴ The point on X-axis which is equidistant form points P and Q is (-7, 0).Read more on Sarthaks.com - https://www.sarthaks.com/856601/find-the-point-on-x-axis-which-is-equidistant-from-p-2-5-and-q-2-9 it HOPE. please MARK ME BRAINLY.

Answer 2

the required point in x-asis is (-7,0).