Question

6. Find the position, nature and size of the image of an object of length 2 cm placed at a distance of 18 cm from a
concave mirror of focal length 12 cm.​

Answer 1

Answer:

nature will be diminished, virtual, erect

Answer 2

Answer:

v = -36

hi = -4

Real and inverted

Explanation:

height of the object : 2

u = -18

f = -12

1\f = 1\v + 1\u

- 1/12 = 1/v - 1/18

-1/12 +1/18 = 1/v

-3+2/36 = 1/v

-1/36=1/v

v = -36

h'/h = -v\u

h'\2= -(-36)/-18

h'/2= -2

h'= -4