6) Find the remainder of (9 x-17) whet
it is divided by (x-2). *
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By remainder theorem,
x-2=0
x=2
p(x)= 9x-17
p(2)= 9(2)-17
= 18-17
=1
Therefore, when 9x-17 is divided by x-2 then the remainder will be 1
x-2=0
x=2
p(x)= 9x-17
p(2)= 9(2)-17
= 18-17
=1
Therefore, when 9x-17 is divided by x-2 then the remainder will be 1
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