Question

6. Find the remainder when
3x - ax2 + 6x - a is divided by x-a​

Answer 1

Answer:

by factor theorem.

x-a= 0

x= a.

by putting the value of x.

Step-by-step explanation:

p(a)= 3(a)-a(a^2)+6a-a

3a-a^3 +6a-a

-a^3+9a-a= a^3+8a.(remainder)..

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Answer 2

Answer:

Step-by-step explanation:

p(x) = x3 - ax2 + 6x - a

x-a=0

x=a

Using remainder theorem

p(a) = (a)3 - a (a)2 + 6a - a

a3 - a3 + 5a = 5a

Thus, remainder is 5a

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