Question

6. Find the result of mixing 10 g of ice at -10°C
with 10 g of water at 10°C. Specific heat capacity
of ice = 2.1 J g- K-I, specific latent heat of
ice = 336 J g- and specific heat capacity of water
= 4.2 Jg-K-
Ans. 0.625 g ice will melt and
temperature will remain 0°C​

Answer 1

Answer:

One calorie is the heat energy required to raise the temperature of 1 g of water from 14.50 C to 15.50 C. The unit calorie is related to the S.I. unit joule as follows:

1 calorie = 4.186 J.