Question

6. Find the smallest 4-digit number which is exactly
divisible by 18, 24 and 32.
[NCERT)​

Answer 1

Answer:

2 is right answer

Step-by-step explanation:

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Answer 2

Answer:

Smallest number divisible by 18,24,32

Factors of 18=2×3×3

Factors of 24=2×3×2×2

Factors of 32=2×2×2×2×2

LCM=2×2×2×2×2×3×3=288

∴288 is the smallest number divisible by 18,24,32

Now, smallest 4 digit number=1000

1000=288×3+136

Remainder=136

But we need to find a number where the remainder is 0

Required number=1000+(288−136)=1000+152=1152

So,1152 is the smallest 4 digit number

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