Math, asked by sohailahmad2078, 8 months ago


6. Find the smallest number which when divided by 12, 15, 18 and 27 leaves as
remainder 8, 11, 14 and 23 respectively.​

Answers

Answered by sakshi15310
0

Answer:

4

Step-by-step explanation:

subtract 8,11,14,23 respectively from 12,15,18,27 the number will be 4 in all case. So, the LCM will be 4

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