6. Find the smallest number which when divided by 12, 15, 18 and 27 leaves as
remainder 8, 11, 14 and 23 respectively.
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Answer:
4
Step-by-step explanation:
subtract 8,11,14,23 respectively from 12,15,18,27 the number will be 4 in all case. So, the LCM will be 4
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