Math, asked by nandydebabrata75, 3 days ago

6. Find the smallest number which, when divided by 12, 15, 18, 24 and 36 leaves no remainder. 7. Find the smallest number which, when increased by one is exactly divisible by 12, 18, 24, 32 and 40. 8. Find the smallest number which, on being decreased by 3, is completely divisible by 18, 36, 32 and 27.​

Answers

Answered by gyaneshwarsingh882
0

Answer:

Step-by-step explanation:

6.) 3

7.) 1439.

8.)

Prime factorize all the given numbers. Hence, if we decrease 867 by 3, 864 will be divisible by all 18, 36, 32 and 27

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