Math, asked by kajalgurjar, 9 months ago


6. Find the smallest number which when divided by
18, 27 and 36 leaves a remainder 5 in each case.​

Answers

Answered by Jyotisna
2

Answer:

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Answered by smrititripaathi
0

LCM of 18, 27, 36= 2×2×3×3×3=180

Smallest number= 108+5= 113.

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