Question

6. Find the speed of a train which leaves Secundrabad at 7p.m. and reaches Bhopal the next
day at 6 am it stops for 1 hour on the way. The distance between Secundrabad and Bhopal
s 10 km. Also find the average speed correct to one place of decimal​

Answer 1

Answer:

for speed

Step-by-step explanation:

Speed = D/T

Distance=10 KM {given}

Time=11hr-1hr[as it stops in the middle] = 10 hrs

speed =10/10=1km/hr

HOPE THIS HELPS!