Question

6. Find the time taken by a 500 W heater to raise the
temperature of 50 kg of material of specific heat
capacity 960 J kg-1 K-1 from 18°C to 38°C. Assume
that all the heat energy supplied by heater is given
to the material.
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Answer 1

Answer:

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Explanation:

Specific heat capacity of material c =

960 J kg-K-1

Change in temperature AT = (38 - 18)°C =

= 20°C (or 20 K)

Power of heater P = 500 W

A Q = mcAT %D

AQ = 50 x 960 x 20

Time taken by a heater to raise the

temperature of material

t= ∆Q / p

50 x 960 x 20 / 500

t = 1920 seconds

t = 32 min