Question

6. Find the total surface area of 1 point
cylinder whose radius is 0.7 cm
and height is 1 m.*
O 443.08 sq.cm
O 440.03 sq. cm
O 445.08 sq. cm
O none of these​

Answer 1

Given :-

• Radius of cylinder = 0.7 cm
• Height of cylinder = 1 m = 100 cm

To Find :-

• T.S.A of cylinder = ?

Solution :-

Let Radius be r and Height be h.

According to Question :-

→ T.S.A of cylinder = 2πrh + 2πr²

→ T.S.A of cylinder = 2πr(h + r)

→ T.S.A of cylinder = 2 × 22/7 × 0.7 (100 + 0.7)

→ T.S.A of cylinder = 44 × 0.1 × 100.7

→ T.S.A of cylinder = 443.08 sq.cm

Therefore,T.S.A of cylinder is A) 443.08 sq. cm.

Extra Shots :-

• Volume of cylinder = πr²h
• T.S.A of cylinder = 2πrh + 2πr²
• Volume of cone = ⅓ πr²h
• C.S.A of cone = πrl
• T.S.A of cone = πrl + πr²
• Volume of cuboid = l × b × h
• C.S.A of cuboid = 2(l + b)h
• T.S.A of cuboid = 2(lb + bh + lh)
• C.S.A of cube = 4a²
• T.S.A of cube = 6a²
• Volume of cube = a³
• Volume of sphere = 4/3πr³
• Surface area of sphere = 4πr²
• Volume of hemisphere = ⅔ πr³
• C.S.A of hemisphere = 2πr²
• T.S.A of hemisphere = 3πr²

Answer 2

GIVEN:-

--》Radius = 0.7 cm

--》Height of cylinder = 100cm

TO FIND:-

--》TSA of cylinder

SOLUTION:-

--》TSA of cylinder = 2πr(h + r)

--》= 2×22/7×0.7(100 + 0.7)

--》= 443.08 sq.cm

HENCE PROVED