Question

(6) Find the value
of 'k' for
which the
equations 2x+ky-3-0, (k-5)x-3y+9=0
have no solution​

Answer 1

Step-by-step explanation:

for no solution

2/(k-5)=k/-3≠-3/9

2/(k-5)=k/-3

-6=k²-5k

k²-5k+6=0

k²-3k-2k+6=0

k(k-3)-2(k-3)=0

k=2,3