Question

6) Find the value of k for whose equation
is x²+2 (k+1)x+2=0 has equal roots​

Answer 1

Answer:

k = -1/2; as discriminant( b²-4ac) = 0

Answer 2

Answer:

discriminant formula b^2-4ac=0

Step-by-step explanation:

ax2+bx+c=0

a=1, b=2(k+1), c=2

put the value in above formula

[2(k+1)]^2_4(1)(2)=0

4(k^2+1+2k) -8=0

4k^2+4+8k-8=0

4k^2+8k-4=0

4k^2+4k+4k-8=0

4k(k+1)+4(k+1)=0

4k+1=0. k+1=0

k=-1/4. k=-1