Question

6. Find the value of k if p(x) = x3 - kx² + 11x + 6 and (x-1) is a
factor of p(x)​

Answer 1

Answer:

(x-1) is a factor x-1=0 x=1 p(x) = x³—kx²+11x—6 p(1) = (1)³—k(1)²+11(1)—6 = 1+k(1)+11(1)—6 = 1+11-6+k = 12

Step-by-step explanation:

ok

Answer 2

Step-by-step explanation:

$\bf \underline{Solution-}$

∵ (x - 1) is a factor of p(x)

∴ By factor theorem, we are p(1) = 0

⇒ (1)³ - k(1)² + 11(1) - 6 = 0

⇒1 - k + 11 - 6 = 0

⇒ 6 - k = 0

⇒k = 6

Hence, the value of k is 6.