Question

6. Find the value of n in 251-1+100=52n-1

Answer 1

Answer:

hope you mean,

25n−1+100=52n−1

⟹52n−2+100=52n−1

⟹52n−15+100=52n−1

Let, 52n−1=t

∴t5+100=t

⟹4t5=100

⟹t=125

So, we get —

52n−1=53

⟹2n−1=3

⟹2n=4

⟹n=2

∴n=2

Answer 2

Answer:

$250 + 100 = 52n - 1$

$350 + 1 = 52n$

$52n = 351$

$n = \frac{351}{52}$

$n = 6.75$