Question

6. Find the value of x in each of the following :plz solve ques 6 ka (b ) plz solve​

Answer 1

Answer:

-4

Step-by-step explanation:

${ \binom{5}{4} }^{ - 3} \times { \binom{4}{5} }^{ - 4x} = { \binom{5}{4} }^{ - 19} \\ \\ { \binom{5}{4} }^{ - 3} \times { \binom{5}{4} }^{ 4x} = { \binom{5}{4} }^{ - 19} \\ \\ { \binom{5}{4} }^{ - 3 + 4x} = { \binom{5}{4} }^{ - 19} \\ \\ so \: \: - 3 + 4x = - 19 \\ \\ 4x = - 19 + 3 \\ \\ x = \frac{ - 16}{4} = - 4$

Answer 2

Answer:

$\frac{5}{4} ^{-3} * \frac{4}{5} ^{-4x} = \frac{5}{4} ^{-19}$

$\frac{5}{4} ^{-3} * \frac{5}{4} ^{4x} = \frac{5}{4} ^{-19}$ ( When we are switching the numerator and denominator the power operation changes)

Now, bases are same

(-3) + (4x) = (-19)

-3 + 4x = -19

4x = -16

x = -4