6.
Find the value (s) of k for which the given
quadratic equations has real and equal roots:
kx (x - 2√5)+ 10 = 0
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Answer:
kx(x-2sq.root 5) +10 = 0
kx2-2sq.root5 kx +10 = 0
b2 -4ac = (-2 sq.root 5k)2 -4(k)(10) >0
= 20k2 -40k >0
4 k(5k-10) >0
20k(k-2)>0
k>0 , k>2
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