Question

6. Find the values of p and q so that (x4 + x3 + 8x + px +q) is divisible by (x2+1).​

Answer 1

Answer:

if 2x+1is divisible by 4x+3x+8x+px+q

then first find the value of x and substitute it in the 4x+3x+8x +px+q

now by solving 2x+1 the value of x is -1/2

so now put it in 4x+3x+8x+ px+q

4(-1/2)+3(-1/2)+8(-1/2)+p(-1/2)+q=0

(-2)+(-3/2)+(-4)+(-p/2)+q,=0

-2-3/2-4-p/2+q=0

now taking LCM

-4-3-8-p+q=0

-15-p+q=0

-p+q=15

q=15+p

now put value of q and find p