Question

6. Find the zeroes of 3x2 + 8x+5 and check the relation ship between zeros and co-
efficients?
si disided byy2+29​

Answer 1

Step-by-step explanation:

To find zeroes we have to factorize given polynomial.

3x^+8x+5

= 3x^+3x+5x+5

= 3x(x+1)+5(x+1)

= (3x+5)=-5/3

(x+1)= -1

therefore, alpha=-5/3 and beta= -1

Relationship between zeroes and coefficients

sum of the zeroes = 8/3

product of the zeroes = 5/3

Answer 2

Answer:

The correct answer of this question is $x =-1 , x = \frac{-5}{3}$

Step-by-step explanation:

Given -  The zeroes of 3 x 2 + 8x + 5

To Find - The zeroes of 3x2 + 8x+5 and the relation ship between zeros and co - efficients .

In an algebraic term, a number or symbol multiplied by a variable or an unknown quantity.

$3x^{2} +8 x +5$

$3x^{2} + 3x +5x +5$

$3x ( x+1 ) + 5 (x+1)$

$( 3x +5 ) (x +1 ) = 0$

$3x +5 =0 \\3x = 5 \\x =\frac{-5}{3}$

and  $x +1 =0 \\x =-1$

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