Question

6)Find the zeroes of the polynomial p(x)=(x+2)(x+3)​

Answer 1

Answer:

ANSWER

p(x)=(x+2)(x+3) This is a quadratic polynomial . It has two zeroes .

Let P(x)=0

⇒(x+2)(x+3)=0

⇒x+2=0,x+3=0

⇒x=−2,x=−3

∴ The zeroes of the polynomial are

−2 and −3.

Answer 2

Answer:

p(x)= (x+2)(x+3)

x+2=0 , x+3=0

x= -2 , x= -3

( -2 , -3 ) are two zeroes