Question

6. Find the zeros of the p(x) = (x - 3)(x+2)
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Answer 1

Answer:

The zeroes of the polynomial are  

3 and -2.

Step-by-step explanation:

p(x)=(x-3)(x+2) This is a quadratic polynomial . It has two zeroes .

Let P(x)=0

⇒(x-3)(x+2)=0

⇒x-3=0,x+2=0  

⇒x=3,x=-2  

∴ The zeroes of the polynomial are  

3 and -2.

Answer 2

Answer:

p(x)=(x-3)(x+2)

=x²+2x-3x-6

=x²-x-6

let x+2=0

x=-2

(-2)²-(-2)-6

4+2-6

=6-6

=0