Question

6. Find the zeros of the polynomial x^2+7x+10

Answer 1

x^2+7x+10=0

x^2+5x+2x+10 = 0

x(x+5) + 2(x+5) =0

(x+5) (x+2) =0

x+5=0. x+2=0

x= -5. x= -2

Answer 2

Answer:

zeroes = -5, -2

Step-by-step explanation:

$x^2 + 7x + 10 = 0\\x^2 + 2x + 5x + 10=0\\x ( x + 2) +5 (x + 2)=0\\(x+2)(x+5) = 0\\\\x = -2, x=-5$