Question

6. Find two consecutive even numbers such that the smaller of the two numbers is 4/5 times the larger number.​

Answer 1

Answer:

If there are two consecutive even numbers and the smallest is 4/5 times the larger number then the numbers are $\frac{8}{3}$ and $\frac{2}{3}$

Step-by-step explanation:

Let A and B be the consecutive even numbers

Where A is the smaller and B is the larger number

So, B = A+2

A= B-2

Also given that

A= 1/4 of B

$A= \frac{B}{4}$

So,

$B-2 =\frac{B}{4} \\\\4B-8=B\\\\3B = 8\\\\B=\frac{8}{3}$

$A= \frac{B}{4} \\\\=\frac{\frac{8}{3} }{4} \\\\=\frac{8}{12} \\\\=\frac{2}{3}$

So the consecutive even numbers are

$\frac{8}{3}$ and $\frac{2}{3}$